math help pretty please?

Question

I have to write 2 sequences of numbers that both start out with the same first 4 numbers but they have to have different continuing numbers can someone do this please

it has to be like geometric sequences like it has a pattern to it

Answer 1

12/1=12 12/2=6 12/3=4 12/4=3.....

24-12=12 12-6=6 6-2=4 4-1=3......
best answer pretty please?

Answer 2

How about:
1 2 3 4 5 6 7 8 9 10 11 12....
1 2 3 4 2 2 3 4 3 3 3 4.....

Answer 3

2 4 6 8 10 12 14
2 4 6 8 6 4 2

is this what you mean? The first four numbers are the same but the continuing numbers are not.

Answer 4

Well, there are many ways to do this, but let's take
1 1 2 3 5 8, ... , where each number is the sum of
the preceding two
and
1 1 2 3 4 5 6, ..., where every number after the second
is the next natural number.
See if you can make up some more!

Answer 5

1 2 3 5 8 13 21 34
Add the last two numbers to get the next.
1 2 3 5 7 10 13 17 21
Add 1 twice, add 2 twice, add 3 twice,etc

Answer 6

this chick is rite.. positive and negative.. OR if it's the first 4 "numbers", then make each number 4 digits.. should have specified this criteria. learn this, because with math "you know it, or you don't".. you just have to understand concept.

Answer 7

1234 2345 3456 4567
1234 2468 4936 9872

Answer 8

ok..so..what? college math? so i basically have no idea what any of that means..sorry =[

Answer 9

I don't get it but you can change it by + to -.