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so I have -x^2 +1 / x^2 - 5x + 6

how would I do this in long division, what's are the steps, answer, please help explain, thanks

2007-07-05 05:30:43 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

your first step would be to find the constant, which if multiplied by x^2, would equal -x^2. That is -1. So when you multiply -1 by the divisior, you get a term -x^2 +5x-6, which is subtracted from -x^2+1. The result is -(5x+5). This is a remainder. Note that the divisor factors to (x-6)(x+1), which means that the resulting remainder would reduce to -5/(x-6).

2007-07-05 05:41:34 · answer #1 · answered by cattbarf 7 · 0 0

I suspect you should have written your expression as
(1-x^2)/(x^2 - 5x + 6), which would become after factoring the numerator and the denominator
(1+x)(1-x)/(x-2)(x-3).
There are no common factors and the expression stands reduced as it is.

2007-07-05 12:44:05 · answer #2 · answered by Tom T 2 · 0 0

Factor -1 from the numerator, then factor the result, and the denominator.

-1(x+1)(x-1)/(x-3)(x-2)

There are no commmon factors so this cannot be simplified.

2007-07-05 12:40:04 · answer #3 · answered by mom 7 · 0 0

ur bad at this. get a tutor.

2007-07-05 12:39:22 · answer #4 · answered by xojessox 5 · 0 0

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