find the quotient of : (x^2 y^7 - 4x^8 y^5) / (x^2 y)
2007-07-05 04:00:50 · 5 answers · asked by how's it going 1 in Science & Mathematics ➔ Mathematics
This is a matter of factoring out the top so that you can cancel the bottom...
(x^2 y^7 - 4x^8 y^5) is the same as saying (x^2 y) (y^6 - 4x^6 y^4)
So the x^2 y terms would cancel
Final answer: y^6 - 4x^6 y^4
2007-07-05 04:04:34 · answer #1 · answered by A C 2 · 0⤊ 0⤋
basic formula
(A - B)/C = A/C - B/C
so
x^2 y^7 - 4x^8 y^5) / (x^2 y) =
= (x^2 y^7) / (x^2 y) - (4x^8 y^5)/(x^2 y)
= y^6 - 4 x^6 y^4
2007-07-05 11:49:58 · answer #2 · answered by buoisang 4 · 0⤊ 0⤋
(x^2 y^7 - 4x^8 y^5) / (x^2 y)
= [ (x^2 y^5)*(y^2 - 4x^6) ] / (x^2 y)
= y^4 * (y^2 - 4x^6
2007-07-05 11:05:03 · answer #3 · answered by mark r 4 · 0⤊ 0⤋
y^4[y^2 - 4x^6]
2007-07-05 11:11:50 · answer #4 · answered by TrAnE 2 · 0⤊ 0⤋
x² y^(5).(y² - 4 x^6) / x² y
y^4.(y² - 4 x^6)
y^4.(y - 2 x³).(y + 2 x³)
2007-07-09 03:59:24 · answer #5 · answered by Como 7 · 0⤊ 0⤋