3x=1x+16
or, 3x-1x=1x+16-1x [subtracting 1x from both sides]
or,2x=16
or,2x/2=16/2 [dividing both sides by 2]
or,x=8
2x+5=1x+8
or,2x+5-1x=1x+8-1x[subtracting 1x from both sides]
or,x+5=8
or,x+5-5=8-5[subtracting 5 from both sides]
or,x=3 ans
2007-07-05 03:59:23
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answer #1
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answered by alpha 7
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First one -> x=8
Second one -> x =3
1st one: 3x = 1x + 16
2x = 16
x = 8
2nd one: 2x+5=1x+8
x=3
2007-07-05 03:59:39
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answer #2
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answered by sportsstar4u 3
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3x=1x+16
subtract 1x from both sides....
3x - 1x = 1x + 16 - 1x
2x = 16
x = 8
2x+5=1x+8
subtract 1x from both sides...
2x + 5 - 1x = 1x + 8 - 1x
1x + 5 = 8
subtract 5 from both sides...
1x + 5 - 5 = 8 - 5
1x = 3
x = 3
2007-07-05 04:00:47
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answer #3
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answered by mark r 4
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3x = x + 16
2x = 16
x = 8
2x + 5 = x + 8
x + 5 = 8
x=3
2007-07-05 04:01:22
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answer #4
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answered by nyphdinmd 7
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3x = x + 16
first put all the terms with x together, and do the calculation:
3x - x = 16
you'll get 2x = 16
doing division will help you to get x = 8 where
x = 16/2 = 8
It's the same as the second one..
goodluck trying
2007-07-05 04:02:30
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answer #5
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answered by darrylng88 2
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x=8 first one x = 3 second one
2007-07-05 04:00:03
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answer #6
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answered by Sole 3
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well the left equation x = 8 and the right equation x = 3
i don't know if you're asking this as to separate equations becuase then those would be the asnwers but if it is and "and" question THEN the answer would be no solution because there is on number x that satisfies both equations
2007-07-05 04:00:16
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answer #7
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answered by Anonymous
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1) x = 8
2) x = 3
2007-07-05 09:07:24
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answer #8
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answered by Shobiz 3
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first problem x is 8 and second is 3. dang it sports star answered before me by 1 second
2007-07-05 03:59:43
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answer #9
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answered by Anonymous
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3x=1x+16
-1x -1x
------------------
2x=16
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2 2
x=8
2x+5=1x+8
-2x -2x
-----------------------
5= -1x+8
-8 -8
------------------------------
-3= -1x
----------------------
-1 -1
x=3
2007-07-05 04:30:54
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answer #10
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answered by its just me 3
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