Momentum is inertia in motion, and is equal to the product of a body's mass and its velocity. For example, if the speed of a projected canonball is doubled, then the momentum is doubled. Or if instead the cannonball's mass is doubled, then the momentum is likewise doubled. Suppose however, that a cannonball's mass is somehow doubled and its velocity is also doubled. The its momentum is:
a) the same
b) doubled
c) quadrupled
d) none of these
Choose only one final answer (please!). A correct answer accompanied by a correct response trumps only a correct answer (or guess) alone. Good luck!
2007-07-05 03:56:08 · 7 answers · asked by ? 6 in Science & Mathematics ➔ Physics
I really need to proofread better! The last sentence should read "Then its momentum is."
2007-07-05 03:58:21 · update #1
Bekki B: Please, if you don't like a question don't answer it. There is enough rudeness here already. The questions are meant for fun.
2007-07-05 05:08:27 · update #2
Answer: C. Which follows from the definition of momentum: mass x velocity. Double the mass times double the velocity equals four times the momentum. A body receives momentum by the application of an impulse -- which is "FORCE multiplied by the TIME during-which-the-force-acts."
We sat that: IMPULSE = change in MOMENTUM.
Ft = delta mv
2007-07-05 05:11:54 · update #3
Well you already have the basics
p = m v
Double m -> 2m, double v -> 2v so p -> 4p the answer is c
2007-07-05 03:59:20 · answer #1 · answered by nyphdinmd 7 · 2⤊ 0⤋
Answer is C, quadrupled. Double (two) the mass times double the velocity means quadruple (four times) the momentum based on the momentum equation you gave defining the momentum as the mathematical product of mass and velociy. I could give a mathematical example. But I think a math principle will suffice; that is, if you do a mathematic operation to one side of the equation, you must do it to the other side where sides are separated by the equal symbol. Since the product of mass and velocity is four times as much, then the momentum on the other side of the equation must be four times as much. It's as simple as that.
2007-07-05 13:14:09 · answer #2 · answered by Piguy 4 · 1⤊ 0⤋
C) Quadrupled.
Imagine the mass and velocity were 1kg and 1 ms^-1 respectively. Momentum would be equal to 1 kg ms^1.
If we double the mass to 2kg and the velocity to 2 ms^-1, then we have 2 x 2 = 4 kg ms^-1.
Hence it has been multiplied by 4 or quadrupled.
2007-07-05 11:01:03 · answer #3 · answered by Doctor Q 6 · 1⤊ 0⤋
p = mv ... so if m is now 2m and v is now 2v then "the momentum is" : c) quadrupled
2007-07-05 11:07:54 · answer #4 · answered by Anonymous · 1⤊ 0⤋
in,itially the momentum is mv, finally2m2v=4mv ans(c)
2007-07-05 11:17:48 · answer #5 · answered by ponnuthurai s 1 · 1⤊ 0⤋
2x2 is 3, no 5. Seriously, now.... This is quite possibly the most trivial question I've seen on here in a week.
If you are going to troll and ask questions just for the sake of asking questions, at least make them interesting.
2007-07-05 11:11:10 · answer #6 · answered by Anonymous · 3⤊ 4⤋
my answer is c)quadrupled if i m right then pls reply me sir
2007-07-05 12:05:05 · answer #7 · answered by UMESH D 1 · 1⤊ 0⤋