(1) x^2 + 4x - 5 = 0
A- (-4,5)
B- (-5,4)
C- (-5,1)
D- (1,5)
(2) p^2 - 8p = 0
A- (8)
B- (-8)
C- (0,8)
D- (-8,0)
2007-07-05 03:55:38 · 4 answers · asked by britz13579 1 in Science & Mathematics ➔ Mathematics
1.
x^2 +4x -5 = 0
x^2 +4x = 5
x^2 +4x +4 = 5 + 4
(x+2)^2 = 9
x+2 = 3 or -3
x = 1 or -5
Answer: C
2.
p^2 - 8p =0
p^2 - 8p + 16 = 0+ 16
(p-4)^2 = 16
p - 4 = 4 or -4
p = 8 or 0
Answer: C
2007-07-05 04:00:08 · answer #1 · answered by A C 2 · 0⤊ 0⤋
Question 1
(x² + 4x + 4) - 4 - 5 = 0
(x + 2)² = 9
x + 2 = ± 3
x = 1 , x = - 5
OPTION C
Question 2
p² - 8p + 16 - 16 = 0
(x - 4)² = 16
x - 4 = ± 4
x = 8 , x = 0
OPTIION C
2007-07-08 20:34:05 · answer #2 · answered by Como 7 · 0⤊ 0⤋
For both questions the option is C.
2007-07-05 03:59:42 · answer #3 · answered by Shobiz 3 · 0⤊ 0⤋
x=7
p=8 (a)
2007-07-05 04:01:24 · answer #4 · answered by Vader Phoenix 1 · 0⤊ 0⤋