Solve algebraically...?

Question

A total of 108 students are in the valley high school marching band. There are 20 more boys than girls in the band. How many boys and how many girls are in the band?

Answer 1

Let

x = girls

x + 20 = Boys

108 = Total girls and boys

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x + x + 20 = 108

2x + 20 = 108

2x + 20 - 20 = 108 - 20

2x = 88

2x / 2 = 88 / 2

x = 88 / 2

x = 44

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There are 44 girls and 64 boys

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Answer 2

Let x be the number of boys in the marching band. If you know there are 20 more boys that girls in the band, then you can represent the number of girls with x-20 (you are subtracting 20 from the number of boys (x)).

So, if the add up the number of boys and the number of girls, you should get 108.

x + (x-20) = 108
x + x - 20 = 108
2x - 20 = 108
2x = 128
x = 64

So, there are 64 boys in the marching band. If there are 20 less girls than boys, then 64-20 = 44 girls. If you want to check your answer to make sure it's right, add the values of the number of boys and the number of girls together, and you should get 108:

64+44=108

Answer 3

Let the number of girls be x
Therefore number of girls is x + 20

x + x + 20 = 108
2x + 20 = 108
2x = 108 - 20 = 88
x = 44

number of girls: 44
number of boys: 64

Answer 4

Let g be the number of girls.
Then the number of boys is g + 20 .....(1)
The total number of students is:
g + (g + 20)
= 2g + 20
Therefore:
2g + 20 = 108
Subtracting 20 from each side:
2g = 88
Dividing by 2:
g = 44.
There are 44 girls, and from (1) there are 64 boys.

Answer 5

x = # of girls
x + 20 = # of boys
108 = total #
so....
108 = x + x + 20
you can solve the rest easily