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ln 1.5 / x = 0.308

how do i get rid of the ln so that i can solve for x?

2007-07-05 00:55:14 · 6 answers · asked by sky l 1 in Science & Mathematics Mathematics

6 answers

Raise the number e to the power of each side of the equation.

ln (1.5/x) = 0.308
e^(ln (1.5/x)) = e^0.308
1.5/x = e^0.308
x = 1.5 / e^0.308

I assumed that 1.5/x was the argument of the ln function. You may have meant that (ln 1.5) was to be divided by x, but in that case you wouldn't need to eliminate the ln function; you'd just evaluate it after performing the simple algebra to isolate x.

In any event, e^(ln(x)) = x for any value or expression for x, so e^(ln (1.5/x)) = 1.5/x, so that's how you get rid of ln.

2007-07-05 01:00:58 · answer #1 · answered by DavidK93 7 · 0 0

ln 1.5 / x = 0.308

Multiply both sides by (x/.308):

(ln 1.5) / .308 = x = .405465/.308 = 1.316445

2007-07-05 00:59:15 · answer #2 · answered by fcas80 7 · 0 0

I assume you mean ln(1.5/x) = 0.308 since there's not much to discuss about the simpler equation ln(1.5)/x = 0.308...

Well, take the exponential of both sides ("exp" is the inverse of "ln").

1.5 / x = exp(0.308)

Then, it's a simple matter to solve for x, namely:

x = 1.5 / exp(0.308)

Equivalenty: x = 1.5 exp(-0.308) =1.102372977...

2007-07-05 01:08:29 · answer #3 · answered by DrGerard 5 · 0 0

Assume question is:-
ln (1.5 / x) = 0.308
1.5 / x = e^(0.308)
1.5 / x = 1.36
1.5 = 1.36 x
x = 1.5 / 1.36
x = 1.1

2007-07-08 20:40:52 · answer #4 · answered by Como 7 · 0 0

if lnx=y
simply x=e^y
hence
ln 1.5/x =.308
1.5/x=e^0.308
hence x=1.5(e^-.308)
e value can be approximated to 2.7

2007-07-05 01:01:52 · answer #5 · answered by stiffmeister 2 · 0 0

ln(1.5/x)=0.308
1.5/x=1.3607
x=1.5/1.3607=1.1024 answer

2007-07-05 01:07:00 · answer #6 · answered by Anonymous · 0 0

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