Solve by factoring: -2y(y + 4) = 0?

Question

A- (-2,4)
B- (0,-4)
C- (2,-4)
D- (0,2)

Answer 1

- 2y(y + 4) = 0
-2y = 0 / ( y+4)
-2y = 0
y = 0 / -2 = 0

or
y+4 = 0 / -2y
y + 4 = 0
y = - 4

therefore, y = (0,-4) which is B

Answer 2

B if i remember correctly you can break this down in to 2 equations.

-2y=0 or y+4=0. if you solve the first equation y=0 and solving the second equation will give y = -4. the only answer that fits this is B.

Answer 3

When you have an equation like this, where it is 0 = some arbitrary sequence of multiplied quantities, all you have to do is set each individual quantity equal to zero. For instance:

-2y=0 and y+4=0
y=0 and y= -4

...so therefore your answer will be (0,-4).

Answer 4

B is the answer.
Plug in 0. 0(4)=0
Plug in -4. 8(0)=0

C and D aren't the answer because when you plug in 2 you get -24.

Answer 5

for a product to be equal to zero it is only required that ONE factor must beequal to zero
So -2y =0 for y=0 and y+4 =0 for y=-4

The answer is B (0,-4)

Answer 6

B

break apart question

2y=0 therefore y=0
y+4=0 therefore y=-4

Answer 7

-2y(y + 4) = 0

this means

-2y = 0 ---> y = 0
y + 4 = 0 ---> y = - 4

so the answer is y = 0 or y = - 4

which is B - (0,- 4)

Answer 8

B, and this is easy what values for y would make the equation 0

Answer 9

(0.-4)

Answer 10

B & C.substitute in eqn