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2007-07-04 17:32:47 · 3 answers · asked by formystudies6 1 in Science & Mathematics Chemistry

3 answers

AgOH will dissolve in excess NH3 to form Ag(NH3)2+ complex, it won't form a stable complex with OH- so it will not dissolve in excess NaOH. The ability to form complex depends on their dissociation constant and solubity product.

2007-07-04 18:27:02 · answer #1 · answered by frutti 2 · 0 1

AgOH is not acidic or amphoteric, so will not dissolve in NaOH.
With ammonia, the very soluble complex ion [Ag(NH3)2]+ forms, so the hydroxide will dissolve in ammonia.

2007-07-05 02:38:25 · answer #2 · answered by Gervald F 7 · 0 0

I am pretty sure that it will desolve in NaOH because the silver hydroxide is a polar ionic compound, and the general rule is that polar substances dissolve in polar substances, and that is NaOH. (NH3 is non-polar (Covalent bonds)

2007-07-05 00:40:22 · answer #3 · answered by T Hobbes 2 · 0 1

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