2007-07-04 12:14:39 · 4 answers · asked by 23344 2 in Science & Mathematics ➔ Mathematics
please show work, formulas or methods
2007-07-04 12:25:26 · update #1
please help
2007-07-04 12:51:30 · update #2
(2x - 3y) (x + 2y)
The coefficients of x would be 2 and 1, and of y would be 2 and 3 or 6 and 1. Since the two coefficients of y have opposite signs (because -6y^2 is negative), the trick is to split it up so that the coefficient of the xy term is 1.
2*2 + (-3)*1 = 1, so having -3y opposite 1x, and 2y opposite 2x is what works.
2007-07-04 12:18:08 · answer #1 · answered by McFate 7 · 1⤊ 0⤋
2x^2+xy-6y^2
= (2x-3y)(x+2y)
2007-07-04 19:21:05 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
it would be (2x-3y)(x+2y). because of the coefficient rule and the order of factorization!!!!!!
hope that helps!!!!
2007-07-04 19:25:09 · answer #3 · answered by *sportygator* 2 · 0⤊ 0⤋
(2x - 3y) (x + 2y)
2007-07-04 19:20:01 · answer #4 · answered by UNIQUE 3 · 0⤊ 0⤋