2007-07-04 12:12:05 · 7 answers · asked by 23344 2 in Science & Mathematics ➔ Mathematics
Please show mork, methods or formulas you used
2007-07-04 12:15:46 · update #1
3x^3-5x^2-2x
=x(3x^2-5x-2)
= 3(3x+1)(x-2)
2007-07-04 12:17:59 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
factor out x
x (3x^2 - 5x - 2)
two numbers that multiply to -6 and add to -5
the two numbers are -6 and 1
since the leading coefficient is not 1. Replace the middle term witht the two numbers
x (3x^2 - 6x + 1x - 2)
factor by groups
x { (3x^2 - 6x) + (1x - 2)}
factor out GCF
x { 3x(x - 2) + 1(x - 2)}
factor out x - 2
x (x - 2) (3x + 1)
2007-07-04 19:18:39 · answer #2 · answered by Ha!! 2 · 1⤊ 0⤋
3x^3 - 5x^2 - 2x
= x(3x^2 - 5x - 2)
= x(x-2)(3x+1)
2007-07-04 19:18:44 · answer #3 · answered by pki15 4 · 0⤊ 0⤋
x(3x^2-5x-2)
2007-07-04 19:19:26 · answer #4 · answered by UNIQUE 3 · 0⤊ 0⤋
x(3x^2-5x-2)
2007-07-04 19:14:36 · answer #5 · answered by blahgoshgurlie♥ 3 · 0⤊ 0⤋
X * (3X + 1) * (X - 2)
2007-07-04 19:17:02 · answer #6 · answered by ahem c 1 · 0⤊ 0⤋
ughhhh!!! i hate that factor crap!!!! but i no the answer. it's x(3x^2-5x-2).
hope that helps!!!!!!!!!!!!!!!
2007-07-04 19:19:12 · answer #7 · answered by *sportygator* 2 · 0⤊ 0⤋