Triangle, what is the best way to find the lenghth of the other two sides?

Question

you have two angles and one side of a triangle. the angles are on the two ends of the known side, what's the best way to find the lengths of the other two sides?
it seams like with the two know angles and a known side (and in the same place) it should be simpler (more simple) than what I am finding by searching. is there a better way when it is set up like this?

tangent to angle: "what's your "sine"?"

Answer 1

if you have one length, for exmple lets say you have the length of the hypotineus, and it's 10. and you have two angles, if you chose one of those angles and manipulate it into youe equation.
say one of the angles, which connects the hypotineus and the adjacent, is 50 degrees.
you want to find the adjacent.

your equaion would be

sin50=x/10
x=10 * sin50

Answer 2

You have two angles and the included side of a triangle. Or states even more succinctly you have angle-side-angle (ASA).

To find the two remaining sides use the Law of Sines.

a/sinA = b/sinB = c/sinC

Suppose you have angles A and B and side c.

C = 180 - A - B

Now you can use

a/sinA = c/sin(180 - A - B)
a = c[sinA / sin(180 - A - B)]

b/sinB = c/sin(180 - A - B)
b = c[sinB / sin(180 - A - B)]

Answer 3

First determine the measure of the third angle (180 minus the other 2) and then apply the law of sines:

a/sin A = b/sinB = c/sinC

good luck!

Answer 4

minus the 180 from the other two sides .than when u have 3 angels and one side .you can use the sine law for two angles and one side
A B c
---- -- ------- --------
a b C