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and how many decibels it is at that boundary?

What's the formula

Does anything special happen at the supersonic-sonic boundary (reduced damage capability maybe?)

2007-07-04 09:40:52 · 2 answers · asked by anonymous 4 in Science & Mathematics Physics

2 answers

You've got it backwards. If a sound wave gets too high in amplitude it becomes a shock wave. For a single frequency (plus its inevitable nonlinear harmonics), the shock transition will occur about when the sound under-pressure reaches (ambient) minus 1 atmosphere (zero absolute pressure). This means the over-pressure is about 1 atmosphere (there's a nonlinear correction). I don't know what that is in Decibels.

Mathematically speaking , a shock results if pressure rises too quickly for the dynamic fluid equation to be solvable for a continuous solution with positive pressure everywhere. Negative pressure is physically meaningless. The only meaningful solution, then, becomes *discontinuous* (in the fluid approximation). The discontinuity is the shock front. A shock wave can be of any amplitude; it has more to do with the abruptness of the pressure rise - like from an explosion.

2007-07-04 10:38:10 · answer #1 · answered by Dr. R 7 · 0 0

I believe that 176 dB is the point where the pressure is +/- one atmosphere.

2007-07-04 22:30:19 · answer #2 · answered by Anonymous · 0 0

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