2007-07-04 08:05:27 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Take the ln or log of both sides:
ln [(0.5)^n] = ln [x]
n * ln(0.5) = ln(x)
n = ln(x) / ln(0.5)
2007-07-04 08:07:48 · answer #1 · answered by whitesox09 7 · 0⤊ 0⤋
Using logs is often very helpful when working with powers.
(0∙5)ⁿ = x (Take the log of the equation).
Log(0∙5)ⁿ = Log x
n Log(0∙5) = Log x
n = Log x / Log(0∙5)
2007-07-04 08:46:19 · answer #2 · answered by Sparks 6 · 0⤊ 0⤋
Take LOG on both sides
n. Log(0.5)= logx
Therefore n= logx/Log(0.5)=-log x.log2
An
( minus logx .log2)
2007-07-04 08:13:22 · answer #3 · answered by RAJASEKHAR P 4 · 0⤊ 0⤋
take the logs on both sides of the equation,
log[(0.5)^n] = log(x)
n log(0.5) = log(x)
n = log(x)/log(0.5)
good luck!
2007-07-04 08:10:33 · answer #4 · answered by alrivera_1 4 · 0⤊ 0⤋
Take the logarithm of both sides :
n log(0,5) = log x => n = logx / log(0,5)
2007-07-04 08:12:35 · answer #5 · answered by ?????? 7 · 0⤊ 0⤋
0.5^n = x is equivalent to ln(0.5^n) = ln(x)
Now ln(0.5^n) = n*ln(0.5)
Thus
n*ln(0.5) = ln(x)
n = ln(x)/ln(0.5)
Try it! By the way, ln(x) is read as "log of x, base e where e = 2.71828182845905..."
2007-07-09 18:50:48 · answer #6 · answered by semyaza2007 3 · 0⤊ 0⤋
n log (0.5) = log x
n = log x / log 0.5
2007-07-08 11:09:58 · answer #7 · answered by Como 7 · 0⤊ 0⤋