3x^4 + 2x^3 -3x+1 / x^2+1
2007-07-04 07:51:05 · 6 answers · asked by how's it going 1 in Science & Mathematics ➔ Mathematics
It just tells me to divide!! Here are the choices:
a. 3x^2-2x+8
b. 3x^2+2x-3
c. 3x^2-2x+1+ x/x^2+1
d.3x^2 +2x-3+ -5x+4 / x^2+1
e. -x^2-3x+16
2007-07-04 08:07:05 · update #1
You have to use long division, which I am going to attempt to do even though it's very difficult to type.
............3x^2 + 2x - 3, Remainder: -5x+4
___________________
x^2+1|3x^4 + 2x^3 -3x+1
.........- 3x^4 + 3x^2
......................2x^3 - 3x^2 - 3x +1
................... - 2x^3 + 2x
......................... -3x^2 - 5x + 1
........................- -3x^2 - 3
................................... -5x + 4
2007-07-04 08:05:49 · answer #1 · answered by whitesox09 7 · 0⤊ 0⤋
Long division I think.
................3x^2 + 2x...- 3
x^2 + 1 ) 3x^4 + 2x^3 + 0x^2 - 3x + 1
................ 3x^4............ +3x^2
............................ 2x^3 - 3x^2 - 3x + 1
............................ 2x^3............ +2x
...................................... -3x^2 - 5x + 1
...................................... -3x^2.......... -3
.................................................. -5x.... +4
So 3x^4 + 2x^3 - 3x + 1 =
= 3x^2 + 2x - 3 + (-5x+4)/(x^2+1)
Hope that helps. Long division is useful, but when there's a remainder you have to be sure and express it as a fraction (just like you would if you were doing long division of whole numbers).
EDIT: I hate this system that it loses all of your formatting; please ignore all of the periods used to space elements out in the problem above. When doing long division of polynomials, be sure and line up like terms before you subtract.
2007-07-04 15:09:04 · answer #2 · answered by Tim P. 5 · 0⤊ 0⤋
The answer is d.3x^2 +2x-3+ -5x+4 / x^2+1
Use long division
x^2 +1 is the divisor
and dividend is 3x^4 + 2x^3 -3x+1
now x^2 is to be multiplied by 3x^2 to make it as 3x^4
so 3x^4 + 2x^3 -3x+1
minus 3x^4 +3x^2 (x^2+1)(3x^2)
------------------------------...
2x^3-3x^2 -3x+1
minus 2x^3 +2x (x^2+1)(2x)
------------------------------...
-3x^2-5x+1
minus -3x^2 -3 (x^2+1)(-3)
------------------------------...
-5x+4
so quotient is 3x^2 +2x-3
and remainder is -5x+4
2007-07-04 15:09:29 · answer #3 · answered by sweet n simple 5 · 0⤊ 0⤋
use long division
(3x^4+2x^3-3x+1)/(x^2+1) = 3x^2+2x-3 +(-2x+3)/(x^2+1)
2007-07-04 15:04:41 · answer #4 · answered by santmann2002 7 · 0⤊ 0⤋
Divide it
x^2+1)3x^4+2x^3-3x+1(3x^2+2x-3
3x^4+ +3x^2
-------------------------------------
+2x^3-3x^2
2x^3+2x
----------------------------------------
-3x^2-5x
-3x^2-3
---------------------------------------------
4-5x
Answer : Q uotient = (3x^2 +2x-3)
Remainder =4-5x
Check:
QX(x^2+1) +(4-5x) = 3x^4+2x^3-3x+1
2007-07-04 15:06:52 · answer #5 · answered by RAJASEKHAR P 4 · 0⤊ 0⤋
Is there another side of the equal sign on that? A zero or a 'y'? Are you being asked to find the factors or reduce it?
2007-07-04 15:02:08 · answer #6 · answered by vpistov 4 · 0⤊ 1⤋