How do I find the limit of x-> 1 for e^-x^2/2?

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How do I find the limit of x-> 1 for e^-x^2/2?

2007-07-04 06:44:21 · 4 answers · asked by mnkbtt10 3 in Science & Mathematics ➔ Mathematics

4 answers

simply substitute 1 in x.
there is an ambiguity in interpreting the ' /2 ' part...

d:

2007-07-04 06:48:06 · answer #1 · answered by Alam Ko Iyan 7 · 1⤊ 0⤋

It depends what the order of operations is

Is is { [ e^(-x) ] ^2 } /2 ?

Or is it [ e^ {(-x^2) / 2} ]

In any case, I don't understand the "limit" part. Just evaluate it for x = 1.

2007-07-04 13:50:01 · answer #2 · answered by morningfoxnorth 6 · 0⤊ 0⤋

limit of x-> 1 for e^(-x^2)/2
put x=1

=e^(-1^2)/2
=1/(2e^1)
=1/(2e)

2007-07-04 13:50:54 · answer #3 · answered by harry m 6 · 0⤊ 0⤋

= 1/2e^x^2
= 1/2e

2007-07-04 13:50:19 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋