5/3(m-2) + 2/5(m+1) =1
what is m equal to?
2007-07-04 06:12:26 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The key to doing this problem is to multiply the numbers in front of the parenthesis first, then group like terms, and then get m by itself by adding/subtracting both sides by the non-m terms. Finally divide the number on the other side of the equals sign by the number in front of m.
So from the second line the equation looks like this:
5/3m - 10/3 + 2/5m + 2/5 = 1
31/15m - 44/15 = 1
31/15m = 1+44/15
31/15m = 59/15
m = (59/15)/(31/15)
m = 59/31 or m approximately equals 1.903.
2007-07-04 06:31:49 · answer #1 · answered by J Kirsch 7 · 0⤊ 0⤋
5/3(m-2) + 2/5(m+1) =1
[25(m-2)+6(m+1)] /15 =1
25m-50+6m+6 =15
31m - 44 =15
31 =15+44
m =59/31
2007-07-04 13:28:07 · answer #2 · answered by candymax 1 · 0⤊ 0⤋
multiply by 15, the lcd:
25(m-2) + 6(m+1) = 15
25m - 50 + 6m + 6 = 15
31m - 44 = 15
31m = 59
m = 59/31
2007-07-04 13:19:57 · answer #3 · answered by Philo 7 · 0⤊ 0⤋
In Unicode the capital M is codepoint U+004D and the lowercase m is U+006D.
The ASCII code for capital M is 77 and for lowercase m is 109; or in binary 01001101 and 01101101, correspondingly.
The EBCDIC code for capital M is 212 and for lowercase m is 148.
The numeric character references in HTML and XML are "M" and "m" for upper and lower case respectively.
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2007-07-04 13:29:06 · answer #4 · answered by Anonymous · 0⤊ 0⤋