for what value of k will these2 equations have non-0 solution?
2007-07-04 04:14:48 · 6 answers · asked by ʞzɹәႨnɹ 2 in Science & Mathematics ➔ Mathematics
Only k = 6.
Why?
Well, we can multiply the first equation by 2
and get
6x+8y = 0
kx + 8y 0.
Subtract the second equation from the
first to get
(6-k)x = 0.
If k<> 6, we can divide by 6-k
and get x = 0, y = 0.
If k = 6, we have a dependent system,
and y = -3x/4,
which has infinitely many nonzero solutions.
This system is an example of what is called
a homogeneous linear system.
2007-07-04 04:31:16 · answer #1 · answered by steiner1745 7 · 0⤊ 0⤋
For k =6, the second will be a multiple of the first equation.
Then any of the infinite number of solutions of the first will also solve the second.
2007-07-04 11:19:13 · answer #2 · answered by Anonymous · 0⤊ 0⤋
k = 6. This will produce an infinite number of solutions.
2007-07-04 11:29:33 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
-4?
2007-07-04 11:20:09 · answer #4 · answered by rh m 2 · 0⤊ 2⤋
great use of the internet
hope you get your answer
2007-07-04 11:18:40 · answer #5 · answered by Anonymous · 0⤊ 2⤋
how dare you
2007-07-04 11:16:55 · answer #6 · answered by Anonymous · 0⤊ 2⤋