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Calculate the solubility of As2S3 in water if the Ksp = 4.4 x 10–27.?

2007-07-04 03:33:19 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

1 answers

As2S3---> 2As++++3S--

Ksp = [As+++]^2 *[S--]^3 if [As2S3]=x [As+++]=2x and [S--]=3x

Ksp = (2x)^2*(3x)^3 = 4x^2*27x^3= 108x^5

x^5 = 4.4*10^-27/108=4.07*10^-29

x=2.1*10^-6mole/L

2007-07-04 03:46:52 · answer #1 · answered by maussy 7 · 2⤊ 0⤋

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