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integrate: 2/squareroot (1-25x^2)

there are two methods i know:

Using the long method, my answer is 2/5sin^-1 5x + C

Using the short alternative method, my answer is 2sin^-1 5x + C

Which answer is correct? Please justify ur explanation & can you derive a conclusion or something. thx

2007-07-04 02:50:02 · 2 answers · asked by Kendra 3 in Science & Mathematics Mathematics

2 answers

You can check the answers by taking the derivatives.
The derivative of the first gives the correct result.
The derivative of the second is 10/sqrt(1-25x^2) and hence incorrect.

2007-07-04 03:13:03 · answer #1 · answered by Anonymous · 1 0

We know that the derivative of f(x) = arcsin(x) = 1/sqrt(1 - x^2).

1/sqrt(1 - 25x^2) = 1/sqrt(1 - (5x)^2) = (1/5) *5/sqrt(1 - (5x)^2)

Since the derivative of 5x is 5, the integral of 5/sqrt(1 - (5x)^2) is arcsin(5x) + C. So, the integral ypou want is

(2/5) arcsin(5x) + C or, in your notation, (2/5) sin^-1(5x) + C, the first answer is correct, the other wrong.

I don't know what you mean by long and short methods, but any all methods have to lead to theb same solution (except for the constant of integration).

2007-07-04 10:58:38 · answer #2 · answered by Steiner 7 · 0 0

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