Two cars are initially 234km apart and traveling toward each other. how many second will they pass each other?

Question

One car is moving a 75 m/s and the other is moving at 88 m/s.
Please explain to me. Thanks

Answer 1

Let them pass each other after t seconds.

Distance traveled by
1st car = 75t m
2nd car = 88t m

Total distance traveled = 163t m

This distance is equal to the initial distance between them.

So
163t m = 234000m
t = 234000/163 = 1435.58 s

Hope this helps.

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Answer 2

Since they are moving towards each other, the relative velocity is the sum of the two velocities = 75 + 88 = 163 m/s

Distance = 234 km = 234000m

Time T = 234000 / 163 = 1435.582822 = 1435. 6 secs approx.

What we have done is effectively stopping one car and moving the other car towards the first one at the speed of 163 m/s from a distance of 234 km.

Where they pass each other will be easy to find out. We just multiply the time with one of the speeds.

1435.6 x 75 = 107.67 km. from the first car

Answer 3

Let there be 2 cars A and B
They are approaching each other.
Let A travel x km when the they pass each other.
So,B will cover a distance of 234-x ....as they were 234km apart at start.

They travel for same time say t.
So,

t = x /speedA = 234-x / 88

solve

x/78 = 234 -x /88

and that will give u the value of x in kms

Then multiply with 1000 to get x in metres and equate it to

x =velocity A * time t

x in metres = 78 * time t

And that will give u t

Answer 4

I hope you are not just asking others to do your homework.

You add the two velocities together to obtain the speed at which they are approaching each other, then use that speed to ascertain how long it will take them to cover the 234 km distances between them.

You will also need to convert the m/s to kph to obtain the correct answer.

Good luck

Answer 5

Add the two velocities and divide the distance by the total velocity.
and try to finish your homework by yourself.