Factor completely: 2x2 - 2x - 12.?

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Factor completely: 2x2 - 2x - 12.

2007-07-03 20:10:35 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

2(x^2-x-6)
2(x-3)(x+2)

2007-07-03 20:12:55 · answer #1 · answered by Anonymous · 0⤊ 0⤋

Factor Completely 2x2-2x-12

2016-10-17 02:16:02 · answer #2 · answered by ? 4 · 0⤊ 0⤋

You meant 2x^2 - 2x -12. If not, the following solution doesn't apply.

2, (x - 3) and (x + 2) are the factors. Check it out by multiplying.

2007-07-03 20:15:53 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋

= 2.(x² - x - 6)
= 2.(x - 3).(x + 2)

2007-07-04 07:11:35 · answer #4 · answered by Como 7 · 0⤊ 0⤋

is that 2x^2 - 2x - 12?

=2(x^2 - x - 6)

=2[(x-3)(x+2)]

2007-07-03 20:13:32 · answer #5 · answered by Jay 4 · 0⤊ 0⤋