2007-07-03 18:16:55 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Physics
If they are perfect mirrors the light would just keep reflecting but since there are no such things the light would dissipate or be absorbed.
2007-07-03 18:20:12 · answer #1 · answered by csblueorder 2 · 0⤊ 0⤋
Assuming a vacuum in the room, the light would eventually be absorbed by the mirrors, as mirrors do not reflect 100% of light. A very small amount of it is converted to heat upon reflection, which heats up the particles of the mirror.
There is no substance which can reflect 100% of light; it is never a purely elastic reaction.
As a side, I suppose the light could be generated by some sort of chemical reaction.
2007-07-03 18:22:22 · answer #2 · answered by Leltos 5 · 0⤊ 0⤋
The light wouldn't be there. If there's nothing but mirrors in a room its impossible for the light to be present without a source.
2007-07-03 18:19:59 · answer #3 · answered by Your Ex Boyfriend 4 · 0⤊ 0⤋
Light is basically just a photon particle so it would bounce around imparting energy onto the mirror heating it up. If its a perfect mirror (no open area) it would do that until it gave off enough energy that it would eventually go below the visible light range.
2007-07-03 18:25:11 · answer #4 · answered by kemistree4 1 · 0⤊ 0⤋
Since the mirrors do not reflect the light 100%, it gets slowly attenuated due to absorption at each reflection. Finally it becomes too less to be detectable.
2007-07-03 20:12:48 · answer #5 · answered by Swamy 7 · 0⤊ 0⤋
No mirror is perfectly reflective, so the light would be quickly absorbed.
2007-07-03 18:55:50 · answer #6 · answered by Anonymous · 0⤊ 0⤋
well if it was traped in a room im sure i would have seen ur U ^_^
2007-07-03 18:20:32 · answer #7 · answered by Anonymous · 0⤊ 0⤋