A ball rools horizontally with a speed of 7.6 m/s off the edge of a tall platform.?

Question

If the ball lands 8.7m from the point on the ground directly below the edge of the platform, what is the height of the platform?

Answer 1

ok you have this
for the horizontal motion:

Vx =7.6m/s
t= ?
Delta X= 8.7m

for the vertical motion

Vi=?
Vf= 0
d=?
a= 9.81 m/s^2
t=0

use Delta X divided by the horizontal velocity to find time

next use d= (Vf * t)- 1/2 (a*t^2)

solve for the vertical distance and you have solved the problem

by the way i just finished 9th grade.... you should be able to do this

Answer 2

You first need to know that the object's horizontal speed never changes, even while it's falling (technically that's true only if you ignore air friction, which they usually let you do in these kinds of problems).

So, figure out how long it takes for something to go (horizontally) 8.7 meters, when its horizontal speed is 7.6 m/sec. Now remember that time, and call it "t".

Secondly, you should know that the vertical distance that a ball drops in any given time, depends not at all on its horizontal velocity. So it will drop the same distance in "t" seconds, whether you drop it straight down or flick it sideways off a table.

You should know the formula for how far something drops in "t" seconds. Use that to figure out how how high the platform is.

That should get you started. I consider it unethical (and bad for your education) to give you the actual answer. (But that won't stop other posters. Sigh.)

Answer 3

I'm not positive how to go about this, but I think I've got it figured out: Disregarding the ball's vertical motion, it traveled 7.6 m/s for a distance of 8.7 meters--> and required a time of (87/76) seconds. We can now take into account gravity and this time using the equation for free fall:

d=.5[(g)(t)^2],

where g is the acceleration due to gravity (9.8 m/s^s) and (t) is the time the object takes to fall to the ground.

d=.5[(9.8m/s^2)(87/76s)^2)]
d=.5[(9.8m/s^2)(1.310422s^2)]
d=.5[(9.8m)(1.310422)]

d=6.4210699m

I may actually be right, who knows? Good luck.

Answer 4

The ball is traveling forward at 7.6 m/s while acceleration toward the ground. First find the time it takes for the ball to travel 8.7 m.

t = s/v
t = 8.7/7.6
t = 1.45 sec

Plug the time into the equation

y = g*t^2/2
y = 9.8 * (1.45)^2/2
y= 6.42 m

Answer 5

your x speed is persevering with trough out how long could it take for some thing traveling at 6.3m/s to return and forth 7.7 m? how tall does a drop could desire to be for it to be in the air that long?