The current flows at .50 m/s.
A) At what angle(s) must the boat be steered?
B) How long does it take to make the round trip? ( assuming that the boat's speed is constant at all times, and neglect turnaround time.)
2007-07-03 16:44:58 · 3 answers · asked by Josh Muller 1 in Science & Mathematics ➔ Physics
Huge piece of information is missing: how wide is the river?
2007-07-03 16:48:19 · answer #1 · answered by Stuart 7 · 0⤊ 0⤋
In order to go directly across the river he has to steer through an angle θ from the direct direction in opposite to the river motion.
sin θ = 0.5 /6.75
θ = 4.25 degree.
The vertical speed is 6.75 cos θ = 6.73m/s.
If S is the distance ,
he covers this distance in time (S / 6.73) s.
For the return trip we assume that he moves directly and hence the time will be the same.
Total time is 2S/ 6.73 s = 0.29 x S seconds.
2007-07-04 05:07:16 · answer #2 · answered by Pearlsawme 7 · 0⤊ 0⤋
Agreeing with Stuart above, will need width data.
2007-07-03 23:52:17 · answer #3 · answered by ? 6 · 0⤊ 0⤋