intergration of (1/(in 0.5)) is?

Question

help is this (in (in 0.5))

Answer 1

im going to assume you mean 1/ln(0.5)

int(1/-ln2)

-int(1/ln2)

= -ln(ln2) + C

since -ln2 = ln0.5

= ln(ln0.5) + C (which is your answer but the +c is important)

Answer 2

Assuming that you are integrating with respect to x and that you have not made a typing error (i.e. missed out an x) then
(1/ln 0.5) is a constant. So answer is:

(1/ln 0.5)x + C where C is an arbitrary constant.

If you are puzzled think of x being in your expression as x^0 which of course is the same as 1. Intgrating x^0 gives
(1/1)*x^1 which is x. Oh, and don't forget the constant.

Answer 3

The above answer is wrong

1 / (ln(0.5)) is a constant

Assuming you are differentiating with respect to x, the derivative is simply
[1 / (ln(0.5))] * x + C

Answer 4

I = ∫ k dx where k = (1/ ln 0.5)
I = k x + C
I = (1 / ln 0.5).x + C