Ok, first off, a quick lesson...
anything to the 0 power = 1
so...
2^0 = 1
x^0 = 1
A negative exponent basically means to "flip" the fraction.
so...
x^-1 = 1 / x
(2/3)^-1 = 3/2
(1/x)^-1 = x
Remember when you're dividing two of the same bases, you subtract exponents:
x^a / x^b = x^(a - b)
And when you're multiplying...
x^a * x^b = x^(a + b)
==================
Ok.... now:
-2 x^-2 y^0
= -2 (1/x^2) (1)
= -2 / x^2
2 x^2 y^7 / 6 x y^-1
= (2/6)(x^2 / x) (y^7 / y^-1)
= (1/3) [x^(2 - 1)] [y^7 * y^1]
= (1/3)(x^1)[y^(7 + 1)]
= (1/3)(x)(y^8)
= xy^8 / 3
2007-07-03 06:26:50
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answer #1
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answered by Mathematica 7
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= -2x^-2 (since Y^0 = 1)
= -2 / X^2
2007-07-03 13:30:08
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answer #2
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answered by spirit dummy 5
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-2x^-2y^0 = -2y^0/x^2 = -2/x^2
2x^2y^7/6xy^-1 = xy^8/3
2007-07-03 13:34:13
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answer #3
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answered by ironduke8159 7
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-2x^-2 y^0
= -2/x^2 (1).....a^0=1
=-2/x^2
2x^2 y^7/6x y^-1
=2x^1 y^8/6
= x y^8/3
2007-07-03 13:29:47
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answer #4
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answered by harry m 6
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Im assuming its supposed to be -2x^(-2y^(0))
The -2y^0 is equal to 1, so it becomes -2x^1, which equals -2x
2007-07-03 13:24:41
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answer #5
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answered by therealchuckbales 5
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Anything raised to the Zero power is 1.
I'm not sure about your notations however...the "^" symbol is usually used to signify "to the power of".
2007-07-03 13:23:35
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answer #6
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answered by jjsocrates 4
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plz do it your self. it is very simple math. if i tell you the anwer you will not learn any thing.
2007-07-03 13:25:25
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answer #7
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answered by Anonymous
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is it science..x= girl and y=boy??
2007-07-03 13:23:56
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answer #8
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answered by Anonymous
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