2007-07-03 05:09:21 · 14 answers · asked by colorado43 3 in Science & Mathematics ➔ Mathematics
2 ohms (res) + j 2 ohms (inductive) = 2.82 ohms (impedance)
thats my deduction
2007-07-03 08:12:59 · answer #1 · answered by JavaScript_Junkie 6 · 1⤊ 0⤋
2 + 2j = 2( 1 + j)
2007-07-03 05:12:37 · answer #2 · answered by Tubby 5 · 0⤊ 0⤋
4
2007-07-03 05:14:23 · answer #3 · answered by Window 4 · 0⤊ 0⤋
2(1 + j)
2007-07-03 05:13:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Impossible to solve the question if there is no value for j...
BUT...
if j = -4, 2 + 2(-4) = -6
if j = -3, 2 + 2(-3) = -4
if j = -2, 2 + 2(-2) = -2
if j = -1, 2 + 2(-1) = 0
if j = 0, 2 + 2(0) = 2
if j = 1, 2 + 2(1) = 4
if j = 2, 2 + 2(2) = 6
if j = 3, 2 + 2(3) = 8
if j = 4, 2 + 2(4) = 10
2007-07-03 05:13:38 · answer #5 · answered by Donny Dutch 4 · 0⤊ 0⤋
2 + 2j. It's already simplified for you.
2007-07-03 05:43:58 · answer #6 · answered by CoolioMADDog 4 · 0⤊ 0⤋
Maybe you mean 2i + 2j. That is the line going from 0,0 to 2,2. The 2i+2j it the vector notation for that line
2007-07-03 05:12:23 · answer #7 · answered by Kris Z 4 · 0⤊ 0⤋
Maybe:
2*sqrt(2)*e^{j*pi/4}
?
2007-07-03 06:21:01 · answer #8 · answered by Sean H 5 · 0⤊ 0⤋
Simplified answer is 2(1 + j). A numerical answer cannot be determined without a value for j.
2007-07-03 05:22:08 · answer #9 · answered by Kyrre 2 · 0⤊ 0⤋
It depends what your j stands for. Often in Electrical Engineering, j is used to represent the imaginary number term, also represented by i. In that case, this number is a complex number, and cannot be reduced to anything else so you leave them in the form z = a+b*i or z = a+b*j where z is now a complex number.
2007-07-03 05:42:58 · answer #10 · answered by Anonymous · 0⤊ 0⤋
Not enough information to assist. We would have to know what the value of J is. So the set of answers with the information you have give could be 4,6, 8,10, 12.....etc
2007-07-03 05:21:00 · answer #11 · answered by mikeae 6 · 0⤊ 0⤋