2x^2 + 13x + 6 = 0
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2007-07-03 03:25:57 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2x^2 + 13x + 6 = 0
2x^2 + (12x + x) + 6 = 0
(2x^2 + 12x) + (x + 6) = 0
2x(x + 6) + (x + 6) = 0
(2x + 1)(x + 6) = 0
2007-07-03 03:36:16 · answer #1 · answered by Mathematica 7 · 1⤊ 0⤋
2x^2 + 13x + 6 = 0
2*6=12
1+12=13
(2x+1)(x+6)=0
then x=-1/2 or -6
2007-07-03 03:34:37 · answer #2 · answered by zohair 2 · 1⤊ 0⤋
2x^2 + 13x +6=(2x + ?) (x+?)
=(2x+ 1)(x+6)=0
now 2x+1=0 or x+6 = 0
if 2x+1=0, 2x=-1 , x=-1/2
if x+6=0, x=-6
answer:
x=-1/2 or -6
2007-07-03 03:34:58 · answer #3 · answered by PoseidenNeptuneReturns 4 · 1⤊ 0⤋
2x^2+13x+6= 2x^2+x+12x+6=0
=x(2x+1) +6(2x+1) =(2x+1)(x+6) =
there fore either (2x+1) =0 or
x+6=0
there fore 2x=-1 or x+-1/2
or
x=-6
2007-07-03 03:32:34 · answer #4 · answered by RAJASEKHAR P 4 · 1⤊ 0⤋
2x^2 + x + 12x + 6 = 0
x(2x + 1) + 6(2x+1) = 0
(x+6)(2x+1)=0
x = -6, -1/2
2007-07-03 03:31:25 · answer #5 · answered by Vipin A 3 · 1⤊ 0⤋
(2x+1)(x+6)=0
2x+1=0 2x=-1 x=-1/2
x+6=0 x=-6
x=-1/2 or -6
2007-07-03 03:31:12 · answer #6 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋
(2x+1)(x+6) = 0
x = -6, -1/2
no real detailed workings necessary...
2007-07-03 03:31:15 · answer #7 · answered by miggitymaggz 5 · 1⤊ 0⤋