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2007-07-03 02:57:37 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
150g C6H23O
150/(6*12 + 23 + 16) = 150/111 = 1.3514 moles
42.7g KO
42.7/(39 + 16) = 42.7/55 = 0.7764 moles
320g FeCl2
320/(56 + 2*35.5) = 320/127 = 2.5197 moles
50g H20
50/18 = 2.7778 moles
2.5197/(1.3514 + 0.7764 + 2.5197 + 2.7778) = 0.339 or m.f.(FeCl2) = 33.9%
2007-07-03 08:51:03 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
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2016-05-17 13:52:06 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Convert each and each merchandise to moles using the respective molecular mass. entire up the moles of all of the products. The mole fraction of FeCl2 is then an trouble-free ratio of the moles of FeCl2 to the grand entire of moles.
2017-01-23 10:38:58 · answer #3 · answered by ? 3 · 0⤊ 0⤋
Calculate the moles of each component.
The answer will be Moles of FeCl2/Total moles.
2007-07-03 04:06:05 · answer #4 · answered by ag_iitkgp 7 · 0⤊ 0⤋