tickets were on sale in three weeks.the third week, twice as many as the tickets were sold in the 1st and 2nd combined.How many tickets were sold in the third week?
2007-07-03 02:33:46 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
there were total 1095 tickets sold.
2007-07-03 02:42:06 · update #1
Week 1 = x
Week 2 = y
Week 3 = 2(x + y)
x + y + 2(x + y) = 1095
x + y + 2x + 2y = 1095
3x + 3y = 1095
3(x + y) = 1095
x + y = 365
so...
week 3 = 2(x + y) = 2 (365) = 730
2007-07-03 02:37:46 · answer #1 · answered by Mathematica 7 · 0⤊ 0⤋
let the total number of tickets sold on the 1st and 2nd week to be x
the tickets sold on third week is 2x (as it is twice the number combined)
2x+x=1095
3x=1095
x=365
no.of tickets sold on third week
=2x
=2(365)
=730
2007-07-03 02:59:04 · answer #2 · answered by Lee YW 1 · 0⤊ 0⤋
730 tickets sold in the 3rd week
2007-07-03 02:48:04 · answer #3 · answered by csmithballsout 4 · 0⤊ 0⤋
x + x/2 = 1095
2x + x = 2190
3x = 2190
x = 730
2007-07-03 03:00:29 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
It is impossible to solve the problem due to the lack of information given.
2007-07-03 02:39:27 · answer #5 · answered by Anonymous · 0⤊ 0⤋
730, good luck
2007-07-03 18:09:40 · answer #6 · answered by Unknown 2 · 0⤊ 0⤋