how many seconds are there in 1 millenium?

Question

how many seconds are there in 1 millenium?

Answer 1

60 seconds/minute
x 60 minutes/hour
x 24 hours/day
x 365.25 days/year(leap year every 4 years)
x 1000 years/millenium
= 31,557,600,000

Answer 2

seconds in an hour: 60*60 minutes= 3600
seconds in a day: 3600 *24 hours= 86400
seconds in a year 86400 * 365 days= 3153600
seconds in a millenium: 3,153,600 * 1,000 years= 31,536,000,000
but don't forget to add leap years, which adds on 250 more days so thats 86400 *250=21600000

So the total for the millenium: 31,536,000,000 + 21,600,000=
31,557,600,000 seconds

Answer 3

The whole leap year situation makes things complicated. In years devisible by 100, there is not a leap year, except for years that are also divisible by 400, at least two of which will fall into any given 1000 year period. The problem is that there may be three of them, as well. Both answers are below:

1000 yrs * 365.25 days * 24 hrs * 60 mins * 60 secs =

31,557,600,000 secs

So, with two years divisible by 400, there would be

31,556,908,800 seconds (above minus 8 days)

With three of them, it would be 31,556,995,200 seconds.(original number above, minus 7 days)

Answer 4

I have seconds after every dinner and especially dessert. So that is 2 each day.
The problem is, I won't be around for a millenium, so I'm not sure how many seconds I'd be able to eat

Answer 5

60 times 60 times 24 times 365.25 times 1000

a bit less actually, every 100 years is not a leap year (1100, 1200 etc) so that means

minus 60 times 60 times 24 times 9

Which makes
(60*60*24*365.25*1000) - (60*60*24*9)
= 31,556,822,400

Just read below that here that every 400 years is a leap year. So if you start a thousand years ago 1100, 1300, 1400, 1500, 1700, 1800 and 1900 are not leap years, 1200, 1600 and 2000 are. So instead of 9 it should be seven.

Which makes:
(60*60*24*365.25*1000) - (60*60*24*7)
= 31,556,995,200

Now sometimes there are leap seconds, so this figure is not entirely exact. Scientifically you should write something like
3.1556995 * 10^10

Good luck!

Answer 6

60 x 60 = seconds in a hour.
3,600 x 24 = seconds in a day.
86,400 x 365 = 31,536,000 seconds in a year.
31,536,000 x 1000 = 31,536,000,000

Now, if every fourth year is a ''leap year'' you must add 250 days worth of seconds:

1,000 / 4 = 250
3,600 x 250 = 900,000

So..
900,000 + 31,536,000,000 = 31,536,900,000

There are 31,536,900,000 seconds in a millenium.

Answer 7

It's a little different depending on how you define the millenium and how leap years could come into play. A 1000 year period without leap years has 31536000000 seconds.

Answer 8

If you only consider the centuries, only those divisible by 4 are leap years. 2000, a leap year the same for 2400 and 2800; 2100 not a leap year, the same applies to 2200,2300,2500,2600,2700 and 2900. Even taking this into consideration an exact figure would not be gained. The best way to answer your question would be to find the exact length of a solar year and do the calculation your self.

Answer 9

1,000 years x 365.25 days x 24 hours x 60 minutes x 60 seconds = 31,557,600,000 seconds

Answer 10

To be exact, 1 - 60, so it is 60 and no any other acceptable answer exist