The three angles of a triangle are 3x, x + 10, and 2x - 40. Find the size of the smallest angle in the triangle?
2007-07-02 21:41:25 · 7 answers · asked by kill 1 in Science & Mathematics ➔ Mathematics
It's 30 degrees.
2007-07-02 21:47:10 · answer #1 · answered by GB 2 · 0⤊ 0⤋
The sum of the angles in a triangle is 180 degrees Then 3x + x+ 10 + 2x - 40 = 180 Solve for x
2016-05-17 06:22:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋
3x + x + 10 + (2x - 40) = 180
because the sum of the three angles in a triangle = 180 degrees
4x + 10 + 2x - 40 = 180
6x - 30 = 180
6x =180 + 30
6x = 210
x = 210 / 6 = 35
3x = 3 * 35 = 105
x + 10 = 35 + 10 = 45
2x - 40 = 2 * 35 - 40 = 70 - 40 = 30
the smallest angle is 30 degrees.
2007-07-02 21:55:57 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The sum of the angles are 180°
So 3x+x+10+2x-40 =180
6x = 180+30
x=210/6=35
the three angles are 3x =105 , x+10= 45 , 2x-40 =30
the smallest angle is 30°
2007-07-02 21:47:11 · answer #4 · answered by maussy 7 · 1⤊ 0⤋
3x +
x+10 +
2x - 40
= 180
6x - 30 = 180
x - 5 = 30
x = 35
smallest?
3x = 105
x +10 = 45
2x - 40 = 30 <============ smallest
2007-07-02 21:49:49 · answer #5 · answered by atheistforthebirthofjesus 6 · 0⤊ 0⤋
smallest angle is 2x -40 = 30 degree
180 degree = 3x + x +10 +2x -40
x = 30degree + 5
2007-07-02 21:51:14 · answer #6 · answered by Trazz 2 · 0⤊ 0⤋
6x-30=180
x=210/6
2007-07-02 21:47:07 · answer #7 · answered by Anonymous · 0⤊ 1⤋