4. A-T; C-G
A's pair with T's and C's with G's.
Adenine and Guanine are a class of molecule called purines
Cytosine and Thymine are pyrimidines.
A base pair has one purine and one pyrimidine.
In RNA, uracil, which differs from thymine only in that uracil lacks a methyl (CH3-) group present in thymine, replaces thymine.
An RNA molecule is typically
2. single-stranded
2007-07-02 18:28:08
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answer #1
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answered by BP 7
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For the first question, choice 4 is correct: A-T; C-G (Adenine-Thymine); (Cytosine-Guanine).
....Under normal cellular conditions, hydrogen bonds only form between specific purine and pyrimidine bases. Adenine and guanine are purines, and cytosine and thymine are pyrimidines. In other words, in a DNA double helix, hydrogen bonds form between purines-pyrimidines only. 2 hydrogen bonds form between adenine and thymine, and 3 hydrogen bonds form between cytosine and guanine. Thus, the C-G bond is stronger than the A-T bond, and thus the C-G bond takes more energy to break than A-T.
The base U, or uracil, is not found in DNA. Uracil replaces thymine in RNA.
For the second question, RNA id typically a single-stranded molecule. If you think about DNA transcription, which is semi-conservative, meaning that one strand serves as the template and the other DNA strand serves to ensure a perfect copy of the DNA is retained. Only 1 mRNA is produced from the DNA double helix, as only a single mRNA strand is used to translate protein.
2007-07-02 18:32:40
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answer #2
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answered by madscientist 3
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The base pairing rule is 4.. Adenine pairs with thymine, cytosine pairs with guanine..
basicly.. purine pairs with pyrimidine.. so..
purine= Adenine, guanin
pyrimidine= Thymine, cytosine...
Rna is a single stranded with ribise sugar as the pentose sugar..
2007-07-02 18:27:57
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answer #3
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answered by Rahimi 2
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A(adenine) T(thymine)
G(guanine) C(cytosine)
RNA is single-stranded
2007-07-02 18:26:09
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answer #4
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answered by Anonymous
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A_G
T-C
Option A is correct
In RNA Thymine (T) does not exist
At the start codon A is paired with U instead of G
2007-07-02 18:22:07
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answer #5
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answered by Carter G 4
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