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the ^ after the e is an exponent, e.x. 2^3=8

2007-07-02 17:59:06 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

2e^5X + 2 = 12
e^5X + 1 = 6
e^5X = 5
5X = ln(5)
X = (1/5)ln(5)
x ≈ 0.3218876

2007-07-02 18:08:06 · answer #1 · answered by Helmut 7 · 0 0

2e^(5x) + 2 = 12
subtract 2 from both sides of the equation
2e^(5x) = 10
divide both sides of the equation by 2
e^(5x) = 5
take the natural logarithm of both sides of the equation
ln x and e^x are inverse functions: ln e^a = a
ln e^(5x) = ln 5
5x = ln 5
x = (1 / 5)ln 5 or (ln (5)) / 5 or ln 5^(1/5)

Answer: (ln (5)) / 5

2007-07-02 18:10:11 · answer #2 · answered by mathjoe 3 · 0 0

is the x in the exponent?

if 2(e^5)*x + 2 = 12
..... x = 5/(e^5)

but, if x is in the exponent.
2[e^(5*x)] + 2 = 12

[e^(5*x)] = 5
5x = ln(5)
solve for x

2007-07-02 18:08:39 · answer #3 · answered by Dominic D 2 · 0 0

e^5x=6
ln(e^5x)=ln6
ln(e^5x)=5x
5x=ln5
x=.3218875825

2007-07-02 19:47:42 · answer #4 · answered by Nishant P 4 · 0 0

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