6,32,_,44,_
40,16,_,_,4
14,_,26,2,_
48,24,10,_,_
22,8,34,20,_
2007-07-02 17:17:14 · 5 answers · asked by bejoulais 1 in Science & Mathematics ➔ Mathematics
According to the first column, the numbers add up to 130. So that means the bottom numbers have to add up to 130 -- which means the last row has to read 22-8-34-20-46. Which means the third row has to go 14-50-26-2-38.
You are on your own from there.
2007-07-02 17:26:37 · answer #1 · answered by wdx2bb@verizon.net 2 · 1⤊ 0⤋
6 32 18 44 30
40 16 42 28 4
14 70 26 2 18
48 24 10 36 32
22 8 34 20 46
130
2007-07-03 00:31:54 · answer #2 · answered by jean_has_cats 2 · 1⤊ 0⤋
Once you realize that each column, row, and diagonal add up to 130 (see first column), it is just a matter of looking for which column, row, or diagonal only has ONE missing entry, and subtracting to figure out what value is needed in that position. Here's the solutions. I hope it helps!
6, 32, 18, 44, 30,
40, 16, 42, 28, 4,
14, 50, 26, 2, 38,
48, 24, 10, 36, 12,
22, 8, 34, 20, 46,
2007-07-03 00:37:43 · answer #3 · answered by math guy 6 · 1⤊ 0⤋
To all intents and purposes it is already solved. All columns, rows, and diagonals must sum to 130.
2007-07-03 00:34:48 · answer #4 · answered by Helmut 7 · 1⤊ 0⤋
645. 8374- =h 7465 tan=87.098 =cos86(645.987)hgd565 lon98. jd643=Tan genitals
2007-07-03 00:28:19 · answer #5 · answered by comethunter 3 · 0⤊ 2⤋