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lewis structure BrSP?

Using the ionization energy chart how much energy will it take to remove only one electron on the surface of Nickel? If you hit the surface of Nickel with a photon that has a wavelength of 90 nm, what will the kinetic energy of that ejected electron be?

Point me in the right direction please =]

sorry can someone tell me how to set this up: If you collect hydrogen gas over water at a temperature of 45OC, what is the volume of just the hydrogen if the pressure of hydrogen is 1.23 atm and the grams of hydrogen was 2.6. What is the volume of the water?

2007-07-02 16:37:49 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

Br-P=S is bent b/c there is a lone pair of electrons on the phosphorus. Also, phosphorus is in the middle b/c that's the most stable structure based on the octet rule. Br-S≡P is plausible but S doesn't form triple bonds.

Energy needed to ionize nickel is 7.635 eV or 1.223E-18 Joules (1eV=1.602E-19 J). The energy of a 90nm photon is E=hc/lambda=6.626E-34 J-s * 3E8m/s / 90E-9m =2.209E-18J
The difference between photon and ionization energies is the kinetic energy.

PV=nRT for the third part n=2.6grams/2.02g/mol
for hydrogen: V(L)=n(0.08206L-atm/molK)(45+273)K/(1.23)atm

for water, you'd need to know the mass of the water vapor to calculate its partial volume

2007-07-03 04:24:59 · answer #1 · answered by anotherhumanmale 5 · 0 0

Data required.

2007-07-03 11:27:23 · answer #2 · answered by ag_iitkgp 7 · 0 0

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