Solve for y...
y/(p-q) = y/(p+q)
thanks
2007-07-02 13:37:55 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
y/(p-q)=y/(p+q)
or,yp-yq=yp+yq [by cross-multiplication]
-2yq=0
Therefore y=0
2007-07-02 13:43:23 · answer #1 · answered by alpha 7 · 1⤊ 1⤋
y=0
2007-07-02 20:47:27 · answer #2 · answered by bealsisland 2 · 0⤊ 0⤋
you cannot solve y in this equation. There must be an error on it. Check it again..
2007-07-02 20:45:31 · answer #3 · answered by Mr. Engr. 3 · 0⤊ 0⤋
y/p-q =y/ p+q
y/p-q - y/p+q =0
y(p+q) -y(p-q)=0
yp +yq -yp +yq =0 (yp cancels)
2yq = 0
2 not = 0
yq =0
y =0/q
y=0
2007-07-02 20:50:33 · answer #4 · answered by ravi s 1 · 0⤊ 0⤋
y/(p-q) = y/(p+q)
(p+q)y = (p-q)y
py + qy = py - qy
2qy = 0
Either q = 0 or y = 0
p can be anything except |q|
2007-07-02 20:44:11 · answer #5 · answered by Steve A 7 · 0⤊ 0⤋
(y(p+q)) / ((p-q)(p+q)) = y (p-q) / ((p+q)(p-q))
the denominators cancel out so just equate the numerators
2007-07-02 20:43:57 · answer #6 · answered by Erin G 2 · 0⤊ 0⤋
y / (p - q) = y / (p - q)
y = (y / [p - q]) * (p - q)
y = y
y - y = 0
y is non-existent.
2007-07-06 09:09:19 · answer #7 · answered by Jun Agruda 7 · 2⤊ 0⤋