help starting the process of solving or maybe explaining how to?

Question

A rectangle has area 23 m^2. Express the perimeter P of the rectangle as a function of the length x of one of its sides.

Answer 1

Area = l*w
Perimeter = 2x + 2y
l = x
w = y

23 = x*y ==> y = 23/x
P = 2x + 2y

P = 2x + 2(23/x)

Answer 2

If one side is the length L=x, then the other side is the width given as W=23/x so that L*W = x*23/x=23.
Then the perimeter is given as

P = 2*(L+W) = 2*(x + 23/x) = 2x + 46/x

Answer 3

some basic formulas:
perimeter (of rectangle) = 2 * (Width + Legnth)
area (rectangle) = Width * Length


Let X be the width
A = Width * Length = 23
A = X * Lenght = 23
so, length = 23/X

"Express P as function of x" means
P = some expression of x
P= 2 * (Width + Length)
P = 2 * Width + 2 * Length
P = 2* X + (2 * 23/X)
P = 2x + 46/x

Answer 4

If one side is x, and the area is 23:

a = L * W
23 = x * W
W = 23/x

... then the other side must be 23/x.

Perimeter is twice one side plus twice the other side:

p = 2*x + 2*(23/x)
p = 2x + 46/x

Answer 5

Let area be A and x, y its length and breadth respectvely. We are given that

A = x.y = 23 m^2 or x = 23/y

P = 2(x + y) = 2 (23/y + y)
= 2( 23 + y^2)/y

P = (46 + 2y^2) / y mts.

Answer 6

Rectangle has sides x and y:

Area, A = x * y
y = A / x

Perimeter = 2x + 2y
in other words;
P = 2x + 2(A/x)

Answer 7

A = 23m^2

w = 23m^2/l

P = 2w + 2l = 2(w+l)

23m^2/l + l^2/l = (23m^2 + l^2) / l

2(23m^2 + l^2) / l = P