Please help!!!?

Question

If the sides of a square are decreased by 2 cm, the area is decreased by 36 cm^2. What were the dimensions of the original square?

Any help is much appreciated!

Answer 1

Let the side of original square is x cm
So area= x^2 cm^2
So
(x-2)^2 =x^2-36
x^2 +4-4x =x^2 -36
4x = 40
x=10

so dimensions of original sqaure is 10 by 10 cm

Answer 2

The original length of the square's side is 10 cm. Because when you decrease the sides by 2cm. The areas decreased is twice 2cm times the length of the orginal side minus 2cm *2 cm. That is 2 * (2 * x) - 2*2 = 36
2 *(2x) - 4 =36
4x - 4 = 36
4x = 40 => x=10 cm

Answer 3

The L be the square's side. Then, it's area is L^2. If the side is decreased by 2, then the area of the new square is (L-2)^2.

According to the statement, L^2 - (L -2)^2 = 36. So,

2(2L -2) = 36 => 2L - 2 = 18 => 2L = 20 => L = 10 cm

Answer 4

This requires a couple equations:

1.) (s - 2)^2 = A - 36
2.) A = s^2

The first equation describes the condition while the second describes the original square. s is the side length while A is the area.

Substitute to get:
(s - 2)^2 = s^2 - 36
s^2 - 4s + 4 = s^2 - 36
-4s + 4 = -36
4s = 40
s = 10

Therefore, the original square has a side length of 10cm.

Answer 5

The original square was 10 by 10
The are of the original = 10 x 10 = 100
That means that 2cm less is 8 by 8
8 x 8 = 64

100-64=36

Answer 6

Original square:

x^2 = A

New Square:

(x-2)(x-2) = A-36
x^2-4x+4 = x^2-36
-4x = -40
x = 10

The original square is 10cm x 10cm for an area of 100 cm^2
The new square is 8cm x 8cm for an area of 64 cm^2

Answer 7

Let x be the original dimensions.

(x-2)(x-2)=x^2-36
So,
x^2-4x+4=x^2-36
And x^2 cancels out so
-4x+4=-36
-4x=-36-4
4x=40
Final answer:
Each side was 10 cm long..

Answer 8

x² - 36 = (x - 2)²
x² - 36 = x² - 4x + 4
4x = 40
x = 10

The original square had sides of 10cm.

Answer 9

im so sry... but u can call 18777-teacher and they might help
still im sry