A turntable of mass 4.63 kg has a radius of 0.086 m and spins with a frequency of 0.537 rev/s. What is its ang

Question

A turntable of mass 4.63 kg has a radius of 0.086 m and spins with a frequency of 0.537 rev/s. What is its angular momentum? Assume the turntable is a uniform disk.

need physics help!! i appreciate it!

Answer 1

ρ = m/πr^2
dI = ρr^2drdθ
I = (2/3)πρr^3 = (2/3)mr
P = Iω = (2/3)mrω
P = 2*4.63*0.086*0.537/3
P = 0.14254844 kg-m/s

Answer 2

H = I * omega

I should be the rotational moment of inertia of a disk. Assuming its spins about the center, then you don't have to include the parallel axis thereom terms. Then for a disk it should be something like m*r^2*k, where k will be like 1/2 or something. Look for a table in your book, in the back probably, that gives moment of inertias for various bodies. watch that you find the inertia about the right axis.