equilibrium state?

Question

in terms of...

change in observable properties
and
energy and entropy state

Answer 1

At equilibrium any reaction seems to have stopped, so there is no observable change - even though both the forward reaction and the backward reaction are still going ahead at full speed.

Delta G = 0 at equilibrium, so any enthalpy change has to be exactly cancelled out by any entropy change multiplied by the temperature:

Delta G = delta H - (T x Delta S).

Answer 2

Delta G = 0 for equilibrium so it follows that

delta H = T* delta S

Answer 3

Data required.