Two parallel cylindrical wires made of lead
have diameters D=4mm and the distance
between their axes is L=5mm.
Both wires are in superconductive state. The wires
carry currents I=60A each in opposite directions.
What is the force of magnetic relpulsion F between the wires per unit length (per 1 meter)?
Note:
Meissner effect: magnetic field does penetrate
inside bulk lead (type I superconductor).
Easy-to-use magnetic force calculator
can be found here:
http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/wirfor.html
2007-07-02 05:54:59 · 4 answers · asked by Alexander 6 in Science & Mathematics ➔ Physics
if you had to repost this 8 times, then maybe it's because no one believes they should have to do your homework for you.
2007-07-02 05:58:13 · answer #1 · answered by If u were wondering, It's me 5 · 0⤊ 0⤋
When an electron travels in a wire a magnetic
energy field is created. this magnetic energy is the product of the moving magnetic force and the distance that it radially travels.
The formulas you refered to are correct. except the direction of the magnetic energy field are opposite.
However the dimensions you give of the cylindrical wires run into each other so the wires are shorting. Hence the circuit is destroyed electrostatically.
2007-07-02 06:23:46 · answer #2 · answered by goring 6 · 0⤊ 0⤋
You appear to be demanding an answer to a question you know how to answer. Assuming it is not an answer you seek you must be looking for natural bi-products of this Q&A forum like moment of connection, a companion or a friend like many of us do.
To harvest these bi-products you'll need to be a little more patient. [8th repost] is a little aggresive.
2007-07-02 06:06:14 · answer #3 · answered by Mark 4 · 0⤊ 0⤋
I want a moment of connection. Pick me, pick me!
Oh wait, I just want to kill time because it's so freakin boring here and I work with old people.
2007-07-02 06:15:01 · answer #4 · answered by - 3 · 0⤊ 0⤋