a boat carrying illegal drugs leaves a port and travels @63km/h.a coast guard cutter leaves the port 24 min. later &travels @75km/h in pursuit of the boat.find the times each has travelled when the cutter overtakes the boat with drugs
2007-07-02 05:40:03 · 3 answers · asked by elva f 2 in Science & Mathematics ➔ Chemistry
Drug boat speed - v1
Coast guard boat speed - v2
time - t
v1t = v2(t - (24/60))
v1t = v2t - v2(24/60)
v1t - v2t = -v2(24/60)
(v1 - v2)t = -v2(24/60)
t = [-v2(24/60)] / [v1 - v2]
t = [-75(24/60)] / [63 - 75]
t = 2.5 hours
Drug boat - 2 hours 30 minutes
Coast Guard boat - 2 hours 6 minutes
2007-07-02 05:45:49 · answer #1 · answered by yeeeehaw 5 · 0⤊ 0⤋
24 minutes is 0.4 hours
so in .4 hours the boat travels 63 x .4 = 25.2 km
The c.g. is going 12 km/hr faster, so it will catch them after 25.2 km / 12 km/hr = 2.1 hr
In 2.1 hr the c.g. goes 2.1 x 75 km/hr = 157.5 km
To double check, the boat goes 2.5 hr x 63 km/hr = 157.5 km which is what you would expect.
2007-07-02 12:46:29 · answer #2 · answered by smilam 5 · 0⤊ 0⤋
s = vt
2007-07-02 12:53:09 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋