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2 answers

ether in general is
R - O - R`
it's peroxide then, is:
R - O - O - R`
once the oxygen is attached, it doesn't matter where it attached, as both oxygens are identical.. In case you have one radioactive one, I don't know.. The ether will probably break at the longer carbon chain, since the formed carbocation will be more stable due to inductive effect..

2007-07-02 05:13:53 · answer #1 · answered by sloth 3 · 0 0

Ethers have a R-O-R' structure, where R and R' are two aliphatic groups (they can be the same).
The peroxide has a R-O-O-R' structure. So the incoming oxygen atom has to break a bond with R or R' and attach. BTW, your grammar and spelling can use some work.

2007-07-02 12:14:03 · answer #2 · answered by cattbarf 7 · 0 0

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