A rectangle has an area given by A=x^2+5x+6.Find expressions for the possible length and width of the rectangle?
2007-07-02 04:42:52 · 8 answers · asked by Berry A 2 in Science & Mathematics ➔ Mathematics
Factor:
A = (x+3)(x+2)
maybe...
L = x + 3
W = x + 2
2007-07-02 04:47:49 · answer #1 · answered by Becky M 4 · 1⤊ 1⤋
The question is basically asking you to factor the expression. Since the formula for the area of a rectangle is length * width, the length and width will be factors of the area expression. Looking for factors of 6 that add up to 5, you will find that the factored form is
(x+2)(x+3).
One of the factors represents the length, and the other represents the width.
Hope this helps.
2007-07-02 04:51:40 · answer #2 · answered by Anonymous · 1⤊ 1⤋
A=x^2+5x+6 = (x+3)(x+2)
Since A rectangle =LW
L= x+3 and w=x+2
2007-07-02 05:56:22 · answer #3 · answered by mathvideosonline.com 2 · 0⤊ 1⤋
A=x^2+5x+6
2007-07-02 04:55:56
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answer #4
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answered by fofo m 3
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A=(x+2)(x+3)
-2
A = (x + 3)(x + 2)
Length and width could thus described by (x+3) and (x+2), for the same value of x.
For the area to be zero, you would need negative values of x, which is not practicable (either a zero area or a negative x).
2007-07-02 04:49:04 · answer #5 · answered by MamaMia © 7 · 1⤊ 0⤋
Area = L*W
L*W = x^2 + 5x + 6
W = (x^2 + 5x + 6 ) / L
W = (x+3)(x+2) / L
2007-07-02 04:48:25 · answer #6 · answered by Grant d 4 · 0⤊ 1⤋
(x + 6)(x - 1) = A
the possible lengths would depend on A BUT both figures would need to be positive whereas we have one positive and one negative which wont work
can you recheck your numbers please?
2007-07-02 04:48:53 · answer #7 · answered by Aslan 6 · 0⤊ 4⤋
What is x? It's not clear
2007-07-02 04:51:06 · answer #8 · answered by Steiner 7 · 0⤊ 1⤋