integrate w.r.t. x
1/( cosx + cosecx)
2007-07-02 03:21:43 · 6 answers · asked by Alan 2 in Science & Mathematics ➔ Mathematics
no answers yet? where are the top contributors?
2007-07-02 03:57:37 · update #1
I have to say that.
I think this is one of those functions no one can find
2007-07-06 00:01:06 · answer #1 · answered by Anonymous · 1⤊ 0⤋
The simplest way to answer that question is by substution method. you start with
1/(cosx + cosecx)
you wanna replace
(cosx + cosecx) = u
so now your integrating 1/u du
Once you integrate that you get.
ln |u| + C
If you subsitute back in you get
ln |cosx + cosecx| + C
2007-07-02 11:29:52 · answer #2 · answered by Smile Alway's 3 · 0⤊ 3⤋
there is a formula to that u know..
1/x = log|x|+C
soo if x = cosx+cosecx
dat means
1/( cosx + cosecx) = log |cosx+cosecx|+C
2007-07-03 09:11:06 · answer #3 · answered by girl 3 · 0⤊ 1⤋
x/(cosx+cosecx) is the answer
Try differentiating it and you'll get your original.
....never mind....there is no answer
2007-07-02 11:00:28 · answer #4 · answered by anotherhumanmale 5 · 0⤊ 1⤋
I have to disappoint you, but I think this is one of those functions no one can find the antiderivative
2007-07-02 12:26:18 · answer #5 · answered by Steiner 7 · 0⤊ 0⤋
I'm on the edge of saying that this problem is incalculable.
2007-07-02 11:45:20 · answer #6 · answered by LIFE HATER 1 · 0⤊ 0⤋