i know gamewise ivanovic kicked shara's *** at the french open but strictly on looks, i really cant decide who's hotter
2007-07-02 03:10:05 · 13 answers · asked by Anonymous in Sports ➔ Tennis
Ivanovic!!! The press in Englang has already dubbed her "the prettiest woman to ever play the game of tennis." She doesn't need an "I'm so sexy" attitude like Kournikova or long legs and blonde hair like Sharapova to garner attention for her looks. Just a gorgeous face and winning smile.
2007-07-02 04:33:29 · answer #1 · answered by irenesmng 1 · 0⤊ 0⤋
On court Maria has the edge, but after the game Sharapova is dime a dozen.
I vote Ivanovic, but...
Gabriela Sabatini wipes the floor with both of them!
2007-07-02 10:48:50 · answer #2 · answered by anerasescovedo 4 · 1⤊ 1⤋
in my opinion, I'd say Ivanovic is prettier.. I'm kinda bored looking at Sharapova all the time.. I suppose she's liked alot because of that blonde hair.. hmm I wonder what she'd look like as a brunette..hmm
..but yeh Ivanovic all the way.
2007-07-02 11:27:44 · answer #3 · answered by Anonymous · 1⤊ 1⤋
Ivanovic definitely...Sharapova come second....then....Nicole Vadisova and Vania King
2007-07-02 10:13:52 · answer #4 · answered by JaxJagsFan 7 · 2⤊ 1⤋
No greater site then Sharapova. Unless Kiera Knightley decides to give it a go.
2007-07-02 10:13:41 · answer #5 · answered by 0utsiders 1 · 2⤊ 1⤋
why pick if you can look at them both. but if i had to pick it would be sharapova because that a*s that you said got kicked is HOT.
2007-07-02 10:23:35 · answer #6 · answered by foooooood 3 · 1⤊ 1⤋
Neither Serena is the hottest her booty is so bootylicious. I love when it is windy at Wimbledon cause I think you know what I mean
2007-07-02 13:10:57 · answer #7 · answered by This Little Baby 1 · 1⤊ 1⤋
for me ivanovic more hotter, more sexy and can play great tennis..
2007-07-02 10:39:08 · answer #8 · answered by nazarudin n 1 · 2⤊ 1⤋
ivanovic
2007-07-02 11:22:11 · answer #9 · answered by Anonymous · 1⤊ 1⤋
sharapova
2007-07-02 13:38:06 · answer #10 · answered by Martin 2 · 1⤊ 1⤋