He has 750 and only needs 6 more to claim the title. How many more games will it take him do you think?
My prediction---26 games from 7-2-07
2007-07-02 02:06:30 · 12 answers · asked by Tommy K 1 in Sports ➔ Baseball
It will happen this month. It depends on if pitchers would want to pitch to him. They walk him a lot.
2007-07-02 02:20:59 · answer #1 · answered by Yahoo Man 1 · 0⤊ 0⤋
Look at their schedule, he needs 6 more home runs, he is a streaky hitter and they have a four game set against Cinncinati...I am thinking that he may do it within the next ten games. Their schedule right now is perfect for him to bomb away against horrible pitching! I say it is sooner rather than later!
2007-07-02 09:38:01 · answer #2 · answered by bdough15 6 · 0⤊ 0⤋
Unless he has a carreer ending injury or takes enough steroids that his head will blow off his shoulders, then he will be passing Aaron the last week in July to the first week in August.
2007-07-02 09:17:40 · answer #3 · answered by Matt P 2 · 0⤊ 0⤋
August 6th against the Nationals.
2007-07-02 09:28:44 · answer #4 · answered by bencas9900 4 · 0⤊ 0⤋
He's on pace to break the HR record by August 2nd
2007-07-02 13:15:23 · answer #5 · answered by yankees 2 · 0⤊ 0⤋
I hope that he gets HOT and breaks it in ST.Louis,the fans here will give him the ovation that he deserves,because the Fans here in my hometown Love this game with a passion that is generations old.I Love this game
2007-07-02 10:07:28 · answer #6 · answered by Ricky Lee 6 · 0⤊ 0⤋
Bonds' birthday is July 24th. Maybe he's deliberately timing the celebration.
2007-07-02 09:30:31 · answer #7 · answered by Chipmaker Authentic 7 · 0⤊ 0⤋
if he gets on a streak by the end of july or the beginning of august.
2007-07-02 09:12:49 · answer #8 · answered by Scooter_loves_his_dad 7 · 0⤊ 0⤋
10th game after the all-star break
2007-07-02 09:11:06 · answer #9 · answered by Jim Shorts 4 · 0⤊ 0⤋
unfortionally i think that it'll take him only like 20 more games. (That steriod buttface)
2007-07-02 09:12:42 · answer #10 · answered by Kevin 1 · 0⤊ 0⤋